Frequency Response of Netwroks (Electronic Engineering) Lab Report

Frequency reply of Netwroks (Electronic Engineering) - Lab subject field Example flow rate was determined by monitoring the emf crossways coke ? resistivity. The CRO was utilise to record the veritable and potentiality waveforms. The higher up procedure was ingeminate for the serial union of a resistor and inductor. Voltage crosswise the inductor was heedful at light speed Hz. The oftenness response of the RC low-pass drip was mensural all over the frequency plod speed of light Hz to coke kilohertz. At R = 1 k?, C = 0.01 F, the fading at 15 to 20 frequencies were logarithmically recorded over this range. This procedure was tell with R= 10 k?. The LF oscillator was affiliated to the RLC series hitch and with R= c ? the voltage across the capacitor and inductor, and accredited through the tour of duty at frequencies amongst 1 kilocycle per second and century kHz determined by measuring the voltage across the series resistor. The band-pass filter roac h was constructed and voltages Vo and Vi measured over the range of frequencies 1kHz to 100 kHz. The band-stop filter circuit was in like manner constructed and Vo and Vi again measured over the range of frequencies 1kHz to 100kHz. A Twin-T filter was so constructed with R1 = R2 = 100 ? and C1=C2=0.01F. ... yard 4.673 0.301 0.00301 1552.492 0.000644 2000 4.627 0.561 0.00561 824.7772 0.001212 3000 4.551 0.83 0.0083 548.3133 0.001824 4000 4.47 1.093 0.01093 408.9661 0.002445 5000 4.37 1.32 0.0132 331.0606 0.003021 6000 4.253 1.596 0.01596 266.4787 0.003753 7000 4.11 1.802 0.01802 228.0799 0.004384 8000 3.962 1.989 0.01989 199.1956 0.00502 9000 3.84 2.123 0.02123 180.8761 0.005529 myriad 3.701 2.268 0.02268 163.1834 0.006128 look-alike1 The mental ability is the gradient of the suck which is 6?10-4 F By reckoning C= 1/2?f Xc and at f =myriad Hz and Xc =163.1834 ? then, C = 1 / 2*?* kibibyte0*163.1834 = 0.4126 F which middling agrees with the observational determines. The mi niature loss between the calculated range and the measured value may be due to imprecise exercises or as a dissolving agent of rounded figures. 2) cadence VL and VR in figure6 with R=100 ? and C=0.01uf Table.2 ? (Hz) VL (v) VR (V) I (A) XL (?) 1/XL 100 1.443 4.379 0.04379 32.95273 0.030347 1000 0.675 4.36 0.0436 15.48165 0.064593 2000 1.299 4.23 0.0423 30.70922 0.032564 3000 1.867 4.028 0.04028 46.35055 0.021575 4000 2.317 3.791 0.03791 61.11844 0.016362 5000 2.709 3.53 0.0353 76.74221 0.013031 6000 3.033 3.273 0.03273 92.66728 0.010791 7000 3.273 2.907 0.02907 112.5903 0.008882 8000 3.328 2.705 0.02705 123.0314 0.008128 9000 3.488 2.496 0.02496 139.7436 0.007156 10000 3.592 2.32 0.0232 154.8276 0.006459 Figure 2 From the gradient, the initiation obtained to be 15.6 mH The inducive reactance XL at 100Hz is XL=2fL=2?3.14?100?15.6?10-3= 9.8 ? At f = 100 Hz from the table in a higher place XL = 32.95273 ? The difference is due to experimental errors and errors in reading of res ults. 3) Measuring Vo , Vi , the gain and calculate the frequency response Table.3 ? (HZ) Vi (V) VO (V) reach out Gain in dBs 100 4.634 4.638 1.000863 0.007494 one hundred sixty